5x^2-32x+11=0

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Solution for 5x^2-32x+11=0 equation:



5x^2-32x+11=0
a = 5; b = -32; c = +11;
Δ = b2-4ac
Δ = -322-4·5·11
Δ = 804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{804}=\sqrt{4*201}=\sqrt{4}*\sqrt{201}=2\sqrt{201}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-2\sqrt{201}}{2*5}=\frac{32-2\sqrt{201}}{10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+2\sqrt{201}}{2*5}=\frac{32+2\sqrt{201}}{10} $

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